Bloch Sphere Basis States: X vs Z Gates & Phase Rotations

7  ·  Verify the X → H → Z Diagram in Qiskit

The following public-API Qiskit program verifies the three transformations, arranges the Bloch spheres in the teaching order X, H, Z, labels the x-axis endpoints, and writes the two superposition formulas below the figure. Install the visualisation dependencies with python -m pip install "qiskit[visualization]".

from pathlib import Path

import matplotlib.pyplot as plt
import numpy as np
from qiskit.circuit.library import HGate, XGate, ZGate
from qiskit.quantum_info import Statevector
from qiskit.visualization.bloch import Bloch


def bloch_vector(state):
    alpha, beta = state.data
    overlap = np.conj(alpha) * beta
    return [
        float(2 * np.real(overlap)),
        float(2 * np.imag(overlap)),
        float(abs(alpha) ** 2 - abs(beta) ** 2),
    ]


zero = Statevector.from_label("0")
one = zero.evolve(XGate())
plus = zero.evolve(HGate())
minus = plus.evolve(ZGate())

assert one.equiv(Statevector.from_label("1"))
assert plus.equiv(Statevector.from_label("+"))
assert minus.equiv(Statevector.from_label("-"))

rows = [
    ("X gate", zero, one, r"Input: $|0\rangle$", r"Output: $|1\rangle$"),
    ("H gate", zero, plus, r"Input: $|0\rangle$", r"Output: $|+\rangle$"),
    ("Z gate", plus, minus, r"Input: $|+\rangle$", r"Output: $|-\rangle$"),
]

fig = plt.figure(figsize=(9.6, 12.6), facecolor="white")

for row_index, (gate, before, after, before_title, after_title) in enumerate(rows):
    for column_index, (state, title, color) in enumerate((
        (before, before_title, "#1565C0"),
        (after, after_title, "#D32F2F"),
    )):
        axis = fig.add_subplot(
            3, 2, row_index * 2 + column_index + 1, projection="3d"
        )
        sphere = Bloch(fig=fig, axes=axis, font_size=13)
        sphere.xlabel = [r"$|+\rangle$", r"$|-\rangle$"]
        sphere.vector_color = [color]
        sphere.add_vectors(bloch_vector(state))
        sphere.render(title=title)

    fig.text(
        0.03, 0.805 - row_index * 0.31, gate,
        rotation=90, va="center", ha="center", fontweight="bold",
    )

fig.suptitle(
    "Bloch-sphere gate order: X, then H, then Z",
    fontsize=19, fontweight="bold", y=0.995,
)
fig.text(
    0.5, 0.018,
    r"$|+\rangle=(|0\rangle+|1\rangle)/\sqrt{2}$"
    r"    and    $|-\rangle=(|0\rangle-|1\rangle)/\sqrt{2}$",
    ha="center", fontsize=13,
)
fig.tight_layout(rect=(0.055, 0.05, 1, 0.975), h_pad=1.4)

output = Path("bloch-sphere-x-h-z-gates.png")
fig.savefig(output, dpi=220, bbox_inches="tight", facecolor="white")
print(output)

8  ·  What the Geometry Establishes

1. Basis states are geometric poles. |0⟩ and |1⟩ point along +z and −z.
2. Superposition includes phase. |+⟩ and |−⟩ have identical computational-basis probabilities but occupy opposite points because their relative phases differ.
3. Single-qubit gates are rotations. X is a half-turn around x, H is a half-turn about the axis halfway between +x and +z, and Z is a half-turn around z.
4. Hadamard changes basis. It maps |0⟩ and |1⟩ to |+⟩ and |−⟩, then reverses that mapping when applied again.
5. A statevector and its Bloch vector are two descriptions of the same one-qubit state. Qiskit provides a direct numerical check of the geometry.

Frequently Asked Questions

Can a Bloch sphere represent more than one qubit?

Not as a complete state description. A Bloch sphere exactly represents one pure single-qubit state. Separate single-qubit spheres cannot display quantum correlations in an entangled multi-qubit state. In fact, if you trace out one qubit of a maximally entangled Bell pair, the individual qubit’s Bloch vector collapses to the exact origin (r = 0, representing the maximally mixed state ρ = ½I). For the mathematical derivation and visual proof, see Two-Qubit Entanglement, the 4 Bell States, and Bloch Collapse.

Why does Z appear to do nothing to |0⟩ and |1⟩?

Z leaves |0⟩ unchanged and maps |1⟩ to −|1⟩. For a basis state that minus sign is global phase, so the Bloch point and computational-basis measurement remain unchanged.

Are X, H, and Z really rotations?

Yes. Ignoring physically irrelevant global phase, X is a π rotation about the x-axis, H is a π rotation about the axis halfway between +x and +z, and Z is a π rotation about the z-axis.

What does the Hadamard gate do on the Bloch sphere?

H swaps the x and z coordinates and reverses y, so it maps the computational z basis to the |+⟩/|−⟩ x basis. Because H is self-inverse, a second application maps those states back.

Why use |+⟩ to demonstrate the Z gate?

The Z gate changes relative phase, which is invisible when the state contains only one computational-basis component. The state |+⟩ contains both components, so Z moves it visibly across the equator to |−⟩.

Deepen your quantum intuition with our step-by-step mathematical and circuit guides: