Euler’s Formula: Why e^(iφ) Is Just Shorthand for a Circle

QUANTUM SERIES 2026
Foundational pre-reading: why e is just shorthand for a circle.

This is the foundational pre-reading for the upcoming Quantum Mechanics series. Before wave functions, probability amplitudes, and the quirks of qubits, one piece of mathematics has to be demystified: Euler’s formula. Quantum physics literature leans on the expression e, the phase factor, on almost every page. Raising a constant to an imaginary exponent looks intimidating at first, but conceptually it is nothing more than elegant shorthand for drawing a circle.

New to the math? Read top to bottom. Comfortable with the complex plane already? Skip ahead to Section 4 to see why quantum mechanics relies on this shorthand.

1  ·  The geometry: mapping the complex plane

On a standard 2D graph, points are plotted against an x-axis and a y-axis. The complex plane keeps the layout but changes the meaning: the horizontal axis measures real numbers, and the vertical axis measures imaginary numbers, the multiples of i. Draw a unit circle, a circle of radius 1, and any point on it is fixed by a single angle φ measured counter-clockwise from the positive real axis. Basic trigonometry gives its two coordinates: the horizontal coordinate is cos φ and the vertical coordinate is sin φ. Placed in the complex plane, that point is the real part plus i times the imaginary part, which is exactly Euler’s formula:

e = cos φ + i sin φ
Re
Im
e
φ
cos φ
sin φ
1
Fig 1: a point e on the unit circle. Its horizontal coordinate is cos φ, its vertical coordinate is sin φ.

As φ increases from 0 to 2π, the point sweeps out a full circle around the origin. The right-hand side spells out the coordinates; the left-hand side, the exponential, is the shorthand for the same thing.

2  ·  The mechanics of i: the ultimate rotator

Why should a circle be written as an exponent? The answer starts by reframing the imaginary unit. Algebraically i is the square root of minus one. Geometrically, multiplying any number by i rotates it 90 degrees counter-clockwise in the complex plane. Start at 1, pointing right. One multiplication by i gives i, pointing straight up. Another gives −1, pointing left. Two more pass through −i and return to 1.

1  ×i  i  ×i  −1  ×i  −i  ×i  1
each ×i is a 90° counter-clockwise turn

Seen this way, i is not really a number at all. It is a rotational operator.

3  ·  The calculus: why the base e?

The base e earns its place through calculus: ex is the only function that is its own derivative, so its rate of change always equals its current value. Feeding the rotational operator i into the exponent and differentiating by the chain rule gives:

ddφ e = i e

That small equation carries a large physical statement. The velocity of the point, the direction it is moving, equals its current position multiplied by i, which means the velocity is always exactly 90 degrees away from the position vector.

90°
e
i·e
Fig 2: the velocity i·e is the position vector turned 90°, so it stays tangent to the circle. Perpetual perpendicular velocity is exactly circular motion.

In geometry and orbital mechanics alike, a velocity that stays perpendicular to the position vector is the signature of perfect circular motion. The exponential therefore encodes the act of tracing a circle, automatically.

4  ·  Why quantum mechanics needs this

Rather than writing out a vector built from a real cosine component and an imaginary sine component every time, physicists write the phase factor and move on. The shorthand packs the coordinates, the radius, and the continuous rotation into one compact exponent. The next articles in this series turn to quantum superposition, where relative phase decides whether amplitudes interfere constructively or destructively. Because that relative phase behaves exactly like an angle travelling around a circle, e is the natural tool for modelling it.


Quantum Series 2026  ·  Foundational pre-reading

✦ Drafted with Gemini by Google, formatted and illustrated with Claude by Anthropic ✦